UR1100/KH0113  Indexed Pendant Sum
Drawings:
Right Handed Sums: # Sums = 2, Max # Summands = 3, (Min, Mean, Max) Sum Values = (12, 12, 13)
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Right Handed Sum Detail:  Click on column name to sort
#  Color  Sum Schema  Sum Cord  Sum Cord Value  # Summands  Summands 

1  p9_{3, 2} : 12_{B}  12  2  p18: 8_{W} + p28: 4_{B}  
2  p10_{3, 3} : 13_{B}  13  3  p19: 4_{BB} + p29: 2_{B} + p39: 7_{W} 
Khipu Notes:
Ascher Databook Notes:
 Construction note: The twisted end of cord 1 is linked through the twisted end of the main cord so that it dangles from the end of the main cord.
 This is one of several khipus acquired by the Museum in 1907 with provenance Ica. The khipus with this designation are UR1100, UR1103, UR1105, UR1109, AS115UR1117, UR1120, UR1123, UR1126, AS129, UR1135, UR1138, UR1141UR1143, UR1146, UR1150, UR1152, UR1161AS162, AS164, AS166, AS171, UR1179UR1180.
 By spacing, the khipu is separated into 3 parts. A single cord dangles from the end of the main cord, then part 1 is 1 group of 6 pendants, part 2 is 6 groups of 810 pendants each, and part 3 is 1 group of 3 pendants. Each pendant in part 1 has one subsidiary which is DB.

 The values of the 6 pendants in part 1 are the sums of the values of the 6 corresponding groups in part 2. (Four of the sums are exact, but on 2 of them, the values on the first and fifth pendants, are less than the group sums by 5 and 4 respectively.)
 The value of the first single cord is the sum of the values of the pendants in part 1. Similarly, the value on its subsidiary is the sum of the values on the subsidiary cords of part 1.
 In part 2, some of the sums of values in corresponding positions in the 6 groups are equal to each other. Some of the sums are equal to the sums of corresponding groups. Specifically:
\[ \sum\limits_{i=1}^6 P_{i2} = \sum\limits_{j=1}^{10} P_{2j} \]\[ \sum\limits_{i=1}^6 P_{i4} = \sum\limits_{j=1}^9 P_{4j} \]and
\[ \sum\limits_{i=1}^6 P_{i3} = \sum\limits_{i=1}^6 P_{i7} \]\[ \sum\limits_{i=1}^6 P_{i5} = \sum\limits_{i=1}^6 P_{i6} \]\[ \sum\limits_{i=1}^6 P_{i8} = \sum\limits_{i=1}^6 P_{i10} \]